0.5x^2+5x+7=0

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Solution for 0.5x^2+5x+7=0 equation: 



0.5x^2+5x+7=0

a = 0.5; b = 5; c = +7;
Δ = b2-4ac
Δ = 52-4·0.5·7
Δ = 11
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{11}}{2*0.5}=\frac{-5-\sqrt{11}}{1}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{11}}{2*0.5}=\frac{-5+\sqrt{11}}{1}
$

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